![geometry - In $\triangle ABC$ with $AB=AC$ and $\angle BAC=20^\circ$, $D$ is on $AC$, with $BC=AD$. Find $\angle DBC$. Where's my error? - Mathematics Stack Exchange geometry - In $\triangle ABC$ with $AB=AC$ and $\angle BAC=20^\circ$, $D$ is on $AC$, with $BC=AD$. Find $\angle DBC$. Where's my error? - Mathematics Stack Exchange](https://i.stack.imgur.com/O6Lat.png)
geometry - In $\triangle ABC$ with $AB=AC$ and $\angle BAC=20^\circ$, $D$ is on $AC$, with $BC=AD$. Find $\angle DBC$. Where's my error? - Mathematics Stack Exchange
In ∆ABC, if AC is greater than AB, then prove that AC AB is less than BC, AC BC is less than AB and BC AB is less than AC.
![∆ABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm (Fig 11.26). The height AD from A to BC, is 6 cm. Find the area of ∆ABC. ∆ABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm (Fig 11.26). The height AD from A to BC, is 6 cm. Find the area of ∆ABC.](https://d138zd1ktt9iqe.cloudfront.net/media/seo_landing_files/b1-1623827121.png)